数学题:在一块边长60m的正方形花坛四边种冬青树
- 时间:2020-06-05 20:41:20
- 分类:数学世界
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数学题:在一块边长60m的正方形花坛四边种冬青树,如果四边横行每间隔2m种一棵,竖列每间隔4m种一棵,这个花坛四周种多少棵冬青树?
数学题解答:先算横行种树情况,横行两头都种(即正方形的顶点上要种)。
60÷2+1=31(棵)
31×2=62(棵)
再算竖列种树的情况,此时四个顶点上刚才已经计算过了,所以竖列种树的情况应为两头都不种。
60÷4-1=14(棵)
14×2=28(棵)
62+28=90(棵)
答:这个花坛四周种90棵冬青树。
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