数学题:在一块边长60m的正方形花坛四边种冬青树

  • 时间:2020-06-05 20:41:20
  • 分类:数学世界
  • 阅读:82 次

数学题:在一块边长60m的正方形花坛四边种冬青树,如果四边横行每间隔2m种一棵,竖列每间隔4m种一棵,这个花坛四周种多少棵冬青树?

数学题解答:先算横行种树情况,横行两头都种(即正方形的顶点上要种)。

60÷2+1=31(棵)

31×2=62(棵)

再算竖列种树的情况,此时四个顶点上刚才已经计算过了,所以竖列种树的情况应为两头都不种。

60÷4-1=14(棵)

14×2=28(棵)

62+28=90(棵)

答:这个花坛四周种90棵冬青树。

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