把八个数平均分成两组,使每组中四个数的积相等
- 时间:2020-05-16 19:48:28
- 分类:数学世界
- 阅读:114 次
把4、6、8、21、22、30、33、35八个数平均分成两组,使每组中四个数的积相等,怎样分?有人吗?
数学题解答:利用“分解质因数”法来解决这个问题。把每个数都分解一下,得出如下结果:
4=2×2 ,6=2×3,8=2×2×2,21=3×7,22=2×11,30=2×3×5
33=3×11 ,35=5×7
再根据后面质因数的情况,把它们平均分配一下,就可以了。质因数中共有八个2、四个3、两个5、两个7、两个11。
最后分出来的情况是:6、8、33、35为第一组;4、21、22、30为第二组。
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