汽车比原计划早到1.5小时到达目的地
- 时间:2020-05-20 15:28:23
- 分类:数学世界
- 阅读:114 次
数学题:汽车从甲地到乙地,原计划每小时行50千米。实际每小时行了65千米,这样汽车比原计划早到1.5小时到达目的地,甲乙两地相距多少千米? 这道题应该怎么解答,我是学生的家长,小孩问我,我也不知道,希望老师指导。
数学题解答:此题可用假设法解决。假设汽车以每小时65千米的速度到达目的地后,继续前行,直到与原计划行驶时间相同。那么,将比计划多行:
65×1.5=97.5(千米)
实际每小时比计划多行:
65-50=15(千米)
计划行驶的时间:
97.5÷15=6.5(小时)
甲乙两地距离:
6.5×50=325(千米)
答:甲乙两地相距325千米。
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