SQL Left Outer Join Tutorial with Example: Employee Bonus
- 时间:2020-10-05 13:15:44
- 分类:网络文摘
- 阅读:123 次
SQL Left Outer Join can be illustrated by the following:

sql-left-outer-join
where the query will take everything from left table and those fields from the right table. Let’s take a look at the following question as a left-outer-join (which is known as left-join) example.
Employee Bonus
Select all employee’s name and bonuses whose bonus is less than $1000.
SQL Schema
Create table If Not Exists Employee (EmpId int, Name varchar(255), Supervisor int, Salary int)
Create table If Not Exists Bonus (EmpId int, Bonus int)
Truncate table Employee
insert into Employee (EmpId, Name, Supervisor, Salary) values ('3', 'Brad', 'None', '4000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('1', 'John', '3', '1000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('2', 'Dan', '3', '2000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('4', 'Thomas', '3', '4000')
Truncate table Bonus
insert into Bonus (EmpId, Bonus) values ('2', '500')
insert into Bonus (EmpId, Bonus) values ('4', '2000')
Table:Employee
+-------+--------+-----------+--------+ | empId | name | supervisor| salary | +-------+--------+-----------+--------+ | 1 | John | 3 | 1000 | | 2 | Dan | 3 | 2000 | | 3 | Brad | null | 4000 | | 4 | Thomas | 3 | 4000 | +-------+--------+-----------+--------+empId is the primary key column for this table.
Table: Bonus
+-------+-------+ | empId | bonus | +-------+-------+ | 2 | 500 | | 4 | 2000 | +-------+-------+empId is the primary key column for this table.
Example ouput:
+-------+-------+ | name | bonus | +-------+-------+ | John | null | | Dan | 500 | | Brad | null | +-------+-------+
The SQL of left-join will return all the employees and their bonuses, however, some employees don’t have bonuses – as they are not shown in the Bonus table. Therefore, the result field (bonus) will be empty for those employees. Thus, we have to explicitly use IS (or IS NOT) operator to check for nullness.
SELECT
Employee.name, Bonus.bonus
FROM
Employee
LEFT JOIN
Bonus ON Employee.empid = Bonus.empid
WHERE
bonus < 1000 OR bonus IS NULL;
–EOF (The Ultimate Computing & Technology Blog) —
推荐阅读:工程问题:甲乙两人合做12天 甲乙两商店中某种商品的定价相同 有甲乙两个书架 还有一元钱去了哪里了 孙老师今年36岁,陈天任今年10岁 小朋友排成一队,从前面数小力排在第10个 陈叔叔和李阿妹共同得到一笔奖金 小红看的故事书一共有多少页 两棵树上共有麻雀24只 租这辆车的车费是多少元
- 评论列表
-
- 添加评论