A×B×C=300,A×C=100,A×4=C

  • 时间:2020-04-27 14:43:30
  • 分类:数学世界
  • 阅读:133 次

数学题:A×B×C=300,A×C=100,A×4=C,求A、B、C各是多少?

数学题解答:把题中给出的三个等式分别编上序号,如下:

①A×B×C=300,②A×C=100,③A×4=C

由①A×B×C=300,②A×C=100可知:B=300÷100=3。

又由②A×C=100,③A×4=C可知:A×A×4=100

即A×A=25,所以A=5

那么C=5×4=20。

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