火车的钟声
- 时间:2020-04-22 15:41:35
- 分类:数学世界
- 阅读:82 次
火车的钟声:小明家离火车站很近,他每天都可以根据车站大楼的钟声起床。车站大楼的钟,每敲响一下延时3 秒,间隔1 秒后再敲第二下。假如从第一下钟声响起,小明就醒了,那么到小明确切判断出已是清晨6 点,前后共经过了几秒钟?
数学题解答:从第一下钟声响起,到敲响第6下共有5个“延时”,5个“间隔”,共计(3+1)×5=20(秒)。
当第6下钟声敲响后,小明要判断是否清晨6点,他一定要等到“延时3秒”和“间隔1秒”都结束后而没有第7下钟声敲响,才能判断出确实是清晨6点。
所以,正确的答案应该是:(3+1)×6=24(秒)。
推荐阅读:5 Beginner’s Tips to Building a WordPress Blog 8 Best Affiliate Marketing Plugins For Your Blog How Many Squares/Rectangles Does a Rubik Cube Have? Find the 10001st Prime Number The Difference Between Sum of Squares and Square of the Sum Number of Steps to Reduce a Number in Binary Representation to O Recursive Depth First Search Algorithm to Compute the Diameter o Find the largest palindrome From the product of two 3-digit numb What is the largest prime factor of the number 600851475143 ? Can we Construct K Palindrome Strings?
- 评论列表
-
- 添加评论