A Math Problem: How old is everybody in the Family?
- 时间:2020-10-07 14:38:56
- 分类:网络文摘
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A Math Problem: Family’s Age
This year, sum of the family ‘s age is 100. There are Dad, Mum, Brother, and Sister in the family. And we know:
- Brother is 8 years younger than Sister.
- Mum is 2 years younger than Dad.
- 10 Years ago, the sum of the family’s age was 65.
So, today, how old is everybody in the family?

Solution
Let’s represent the ages of everybody using the following letters:
B – brother
D – dad
M – mum
S – sister
So, B + D + M + S = 100
B + 8 = S
M + 2 = D
Ten years ago, the age difference should be -40 (four people each 10 years younger), however, the difference is only 35 (100 – 65), that means little brother was not born yet 10 years ago.
The actual difference is (65 – 60) = 5, which mean that little brother was born 5 years ago – therefore, the sum was 5 years less than expected 10 years ago.
Therefore,
B = 5
S = 13
B + S = 5 + 13 = 18
Then, D + M = 100 – (B + S) = 82
We know D – M = 2
Adding both sides:
2 * D + (M – M) = 82 + 2
D = 42
M = 40
Let’s verify the answer:
This year, D + M + B + S = 42 + 40 + 5 + 13 = 100
D – M = 42 – 40 = 2
S – B = 13 – 5 = 8
10 years ago, B = 0 (brother was not born), and
(D – 10) + (M – 10) + (S – 10) + 0 = 32 + 30 + 3 = 65
Bingo!
–EOF (The Ultimate Computing & Technology Blog) —
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