How to Determine the Armstrong Number?

  • 时间:2020-09-21 09:15:21
  • 分类:网络文摘
  • 阅读:72 次

The k-digit number N is an Armstrong number if and only if the k-th power of each digit sums to N. Given a positive integer N, return true if and only if it is an Armstrong number.

Example 1:
Input: 153
Output: true
Explanation:
153 is a 3-digit number, and 153 = 1^3 + 5^3 + 3^3.

Example 2:
Input: 123
Output: false
Explanation:
123 is a 3-digit number, and 123 != 1^3 + 2^3 + 3^3 = 36.

Note:
1 <= N <= 10^8

Python to Check if a Integer is Armstrong

Do what it says. The solution should be quite intuitive. Two things need to be resolved: get the number of digits which could be done via converting to string and get the length or using the log10 math function. The second is to compute a^b which in Python this could be done simply by a**b.

Then, we need to extract the right-most digit by do the moduluo ten, and do the integer division using // in Python..

1
2
3
4
5
6
7
8
9
10
class Solution:
    def isArmstrong(self, N: int) -> bool:
        s = 0
        n = N
        l = len(str(N))
        while n > 0:
            t = n % 10
            n //= 10
            s = s + (t ** l)
        return s == N
class Solution:
    def isArmstrong(self, N: int) -> bool:
        s = 0
        n = N
        l = len(str(N))
        while n > 0:
            t = n % 10
            n //= 10
            s = s + (t ** l)
        return s == N

–EOF (The Ultimate Computing & Technology Blog) —

推荐阅读:
网站建设容易忽略的6个地方  如何检查网站是否被竞争对手Negative SEO攻击?  站长创业经验分享  屌丝站长的平凡创业路  如何做让站长赚钱更容易?做好网站浏览体验  奇妙的虹吸现象|小学作文  布达拉宫|小学作文  难忘的一节课|小学作文  我们班的“接话王”|小学作文  好习惯从小做起|小学作文 
评论列表
添加评论