四次相遇求全程问题
- 时间:2020-06-17 18:43:17
- 分类:数学世界
- 阅读:120 次
四次相遇求全程问题:甲乙两车分别从AB两地出发,并在AB两地间不停的往返行驶,已知甲车速度是15千米每小时,乙车速度是25千米每小时。甲乙两车第三次相遇地点与第四次相遇地点相距100千米。求AB两地之间的距离是多少?怎么解?懵了!这个问题好像有些难哦!太难了,对我来说。
因为两车速度分别是15KM和25KM,所以:首先速度比是3:5,这样就可以把全程分为8等分,第一次相遇甲走3等分,乙走5等份。以后每次相遇甲走6等份,乙走10等份。第三次和第四次之间有四个间隔,100÷4=25,25×8=200。
第一次两人在两端,第一次相遇两人合走一个全程。相遇后两人从同一地点相背而走,要合走两个全程才能相遇。(本题由群管理员素心兰老师解答)

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