如图平行四边形ABCD的周长为72厘米

  • 时间:2020-06-10 18:36:27
  • 分类:数学世界
  • 阅读:77 次

数学题:如图平行四边形ABCD的周长为72厘米,以BC为底,高为10厘米;以CD为底,高为15厘米.那么平行四边形的面积是多少?[图片]

反比例解应用题

数学题解答:无论以哪边为底,平行四边形的面积是不变的。面积一定时,平行四边形的底和高成反比例

所以,BC和CD两底边的比,应是两底边上高的反比。

即BC:CD=15:10=3:2

又由于知道了平行四边形的周长,所以可以分别算出两条底边。

72÷(3+2+3+2)=7.2(厘米)

BC=7.2×3=21.6(厘米),CD=7.2×2=14.4(厘米)

平行四边形面积是:21.6×10=216(平方厘米)[面积也可以用另外一对底和高来计算。这里为什么选21.6和10,你懂的……]

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