数学题:甲乙两种皮鞋的原价相同，换季时，甲种皮鞋按五折优惠，乙种皮鞋按四折销售。李老师用216元买了这两种皮鞋，求每双鞋鞋的原价是多少？

数学题解答：由于两种皮鞋原价相同，所以可以设每双皮鞋原价是x元。这样用方程解答的过程就是：

甲皮鞋一双的价钱　+　乙皮鞋一双的价钱　＝　216

50%x + 40%x =216

0.9x = 216

x = 240

答：每双皮鞋原价是240元。

推荐阅读：
How to Design a Snake Game?　 How to Design a Two-Sum Data Structure?　 The MySQL If and Case Statement Exercise: How to Swap Elements i　 Compute the Number of Ways to Paint the House via Dynamic Progra　 How to Paint The Houses using Minimal Costs via Dynamic Programm　 Relative Sort Array Algorithm: Sort Array Based on Predefined Se　 Classic Unlimited Knapsack Problem Variant: Coin Change via Dyna　 How to Remove Vowels from a String in C++?　 The Beginners’ Guide to Trie: How to Use the Trie in C++?　 5 Ways To Revamp Your 40 Hour Work Week