红梅本来有几粒糖
- 时间:2020-05-29 14:54:04
- 分类:数学世界
- 阅读:112 次
明学、红梅、美玲3个人一个有73粒糖, 假如美玲吃了3粒糖,红梅和美玲的糖数一样,红梅给明学2粒的话,明学的是红梅的2倍,红梅本来有几粒糖?
数学题解答:此题可以利用份数来解答。“假如美玲吃了3粒糖,红梅和美玲的糖数一样”说明美玲本来比红梅多3粒糖。去掉美玲的3粒糖,这时两人就同样多了,此时总数变成了:73-3=70(粒)。
当红梅给明学2粒糖时,明学的糖是红梅的2倍。此时红梅的糖少了2粒,而明学的则多了2粒。如果把此时红梅的糖看成1份,那么明学的糖就是2份。而美玲这时比红梅多了2粒,也就是可以看成比1份多2粒糖。去掉美玲的2粒糖,那么糖果总数变成了:70-2=68(粒)。这时明学、红梅、美玲三人糖果的份数分别是:2份、1份、1份。可以求出每份是多少个糖:68÷(2+1+1)=17(粒),红梅是给了明学2粒才变成17粒的,说明她原来有:17+2=19(粒),题目得解。
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