数学题：李白提壶去打酒，遇店加一倍，遇花喝一斗，三次遇店，三次遇花，喝完杯中酒，请问壶中原有都少酒？

数学题解答：

用方程解: 设:壶中原有X斗酒。

一遇店和花后，壶中酒为:2X-1;

二遇店和花后，壶中酒为:2(2X-1)-1;

三遇店和花后，壶中酒为:2[2(2X-1)-1]-1＝0

求出X即可。

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