数学题：甲、乙两人从相距100米的两点同时出发，相向而跑，跑到另一点时立即返回。甲每秒跑6.5米，乙每秒跑5.5米。经几秒钟两人第二次相遇？（由“水阳光-资优网”同学提问）

数学题解答：这样跑步的方式，到两人第二次相遇时，两个所行路程的总和，相当于三个全程。如果对这一结论不理解，可以自己画图看看。也可以看《求AB两站距离的问题》这篇文章中的图。

弄懂了这一点，就好做了。下面用方程解：

设x秒后两人第二次相遇。

(6.5+5.5)x=100×3

12x=300

x=25

答：经25秒后两人第二次相遇。

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