数学题:一只蚂蚁从墙根竖直向上爬到墙头用了4分钟，从墙头沿原路返回到出发点用了3分钟。若蚂蚁第二分钟比第一分钟多爬1分米，第三分钟比第二分钟多爬1分米，……，整个过程中，每分钟爬过的路程都比前一分钟多1分米，则墙高（ ）米。（提问者：民风）

数学题解答：此题可用方程来做，等量关系是上与下的总路程是相等的。但不要设墙高，而是设第一分钟爬x米。
上　　　　　　　＝　　　下
x+x+1+x+2+x+3=x+4+x+5+x+6
4x+6=3x+15
x=9

墙高：4x+6=4×9+6=42（米）

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