数学题:9个队员进行单循环制猜丁壳比赛
- 时间:2020-04-27 14:43:30
- 分类:数学世界
- 阅读:127 次
数学题:9个队员进行单循环制猜丁壳比赛,每人胜一场积3分,平一场积1分,负一场不得分,比赛结束后,发现有一半的比赛没有分出胜负(即平局),前8人共得72分,问第9人胜了几场?
数学题解答:
9人共赛36场:8+7+6+5+4+3+2+1=36
一半平局,共得2×18=36(分)
18场分出胜负,共得3×18=54(分)
第9人得:36+54-72=18(分)
他(她)的胜负情况可能有两种方式:胜6负2,或胜5平3。
答:第9人可能胜了6场,或5场比赛。
[PS:“猜丁壳”是地道的老北京话,猜丁壳的意思就是“石头、剪子、布”,是一种猜拳游戏。起源于中国,然后传到日本、朝鲜等地,随着亚欧贸易的不断发展它传到了欧洲,到了近现代逐渐风靡世界。]
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