Factory Design Pattern in Object Oriented Design Programming

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：122 次
In OOP (Object Oriented Programming), we use inheritance to achieve the polymorphism. The factory design pattern allows you to create/manage different types of classes in a single place. Let’s say, we have a abstract class Animal that... ...

Finding the Lucky Numbers in a Matrix

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：122 次
Given a m * n matrix of distinct numbers, return all lucky numbers in the matrix in any order. A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column. Example 1: Input: matrix = ... ...

How to Balance a Binary Search Tree using Recursive Inorder Trav

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：125 次
Given a binary search tree, return a balanced binary search tree with the same node values. A binary search tree is balanced if and only if the depth of the two subtrees of every node never differ by more than 1. If there is more than one ... ...

Applicable Accounting Software For Churches

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：116 次
5-easy-to-use-seo-tools Sunday service brings us all together to a place of worship. And though there are many ways to carry out Christian services, donating is, perhaps, the most popular. 1 Peter 4:10 “As each one has received a special gi... ...

Dynamic Programming (Memoization) to Sort Integers by The Power

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：115 次
The power of an integer x is defined as the number of steps needed to transform x into 1 using the following steps: if x is even then x = x / 2 if x is odd then x = 3 * x + 1 For example, the power of x = 3 is 7 because 3 needs 7 steps to ... ...

Depth First Search and Breadth First Search Algorithm to Open th

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：129 次
There are N rooms and you start in room 0. Each room has a distinct number in 0, 1, 2, …, N-1, and each room may have some keys to access the next room. Formally, each room i has a list of keys rooms[i], and each key rooms[i][j] is ... ...

How to Remove Zero Sum Consecutive Nodes from Linked List using

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：125 次
Given the head of a linked list, we repeatedly delete consecutive sequences of nodes that sum to 0 until there are no such sequences. After doing so, return the head of the final linked list. You may return any such answer. (Note that in ... ...

How to Design Underground System using Several Hash Maps?

  • 时间：2020-09-10 13:03:17
  • 分类：网络文摘
  • 阅读：124 次
Implement the class UndergroundSystem that supports three methods: 1. checkIn(int id, string stationName, int t) A customer with id card equal to id, gets in the station stationName at time t. A customer can only be checked into one place ... ...

Sum of Multiples of 3 and 5

  • 时间：2020-09-10 12:55:33
  • 分类：网络文摘
  • 阅读：117 次
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. Let’s declare a Javascript function to sum up ... ...

Sum of Even Fibonacci Numbers

  • 时间：2020-09-10 12:55:33
  • 分类：网络文摘
  • 阅读：124 次
Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, … By considering the terms in the Fibonacci sequence whos... ...