How to Design a Snake Game?

  • 时间:2020-09-23 15:50:46
  • 分类:网络文摘
  • 阅读:104 次

Design a Snake game that is played on a device with screen size = width x height. Play the game online if you are not familiar with the game.

The snake is initially positioned at the top left corner (0,0) with length = 1 unit.

You are given a list of food’s positions in row-column order. When a snake eats the food, its length and the game’s score both increase by 1.

Each food appears one by one on the screen. For example, the second food will not appear until the first food was eaten by the snake.

When a food does appear on the screen, it is guaranteed that it will not appear on a block occupied by the snake.

Example:
Given width = 3, height = 2, and food = [[1,2],[0,1]].

1
Snake snake = new Snake(width, height, food);
Snake snake = new Snake(width, height, food);

Initially the snake appears at position (0,0) and the food at (1,2).

|S| | |
| | |F|

snake.move(“R”); – Returns 0

| |S| |
| | |F|

snake.move(“D”); – Returns 0

| | | |
| |S|F|

snake.move(“R”); – Returns 1 (Snake eats the first food and right after that, the second food appears at (0,1) )

| |F| |
| |S|S|

snake.move(“U”); – Returns 1

| |F|S|
| | |S|

snake.move(“L”); – Returns 2 (Snake eats the second food)

| |S|S|
| | |S|

snake.move(“U”); – Returns -1 (Game over because snake collides with border)

snake_grows How to Design a Snake Game? c / c++ data structure design questions games

The Snake Game in Magik

Snake Body: Double Ended Queue

The Snake Body can be stored using the double-ended queue, which we can push to the front and pop from the back.

1
deque<vector<int>> body;
deque<vector<int>> body;

Snake Food: Vector

We can use a std::vector to store the list of food for the snake to eat.

1
vector<vector<int>> food;
vector<vector<int>> food;

Design a Snake Game

We follow the logics as we play the Snake Game:

  1. Move the head of the snake as directed, and return -1 if the head is out of the boundary.
  2. If the head position is now at the food, push the food to the front of the body, erase the food, increment the score, and the snake body will grow one.
  3. Otherwise, the snake needs to move one step forward, then we can pop one from the snake’s tail. And check if the updated heads position is in the snake body, if yes, return -1, otherwise, push the new head to the front of the snake body.

The snake can chase its tail without dying. That is why we need to pop one from tail first before we move the snake head forward. The following C++ code illustrates the design of the snake game.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
class SnakeGame {
private:
    deque<vector<int>> body;
    int W, H;
    vector<vector<int>> food;
    int score = 0;
 
public:
    /** Initialize your data structure here.
        @param width - screen width
        @param height - screen height 
        @param food - A list of food positions
        E.g food = [[1,1], [1,0]] means the first food is positioned at [1,1], the second is at [1,0]. */
    SnakeGame(int width, int height, vector<vector<int>>& food) {
        this->W = width;
        this->H = height;
        this->food = food;
        body.push_back({0, 0});
    }
    
    /** Moves the snake.
        @param direction - 'U' = Up, 'L' = Left, 'R' = Right, 'D' = Down 
        @return The game's score after the move. Return -1 if game over. 
        Game over when snake crosses the screen boundary or bites its body. */
    int move(string direction) {
        auto head = body.front();
        int r = head[0];
        int c = head[1];
        for (const auto &ch: direction) {
            switch (ch) {
                case 'U':
                    r --;
                    break;
                case 'L':
                    c --;
                    break;
                case 'R':
                    c ++;
                    break;
                case 'D':
                    r ++;
                    break;
                default:
                    return -1;
            }
            if (r < 0 || c < 0 || c >= W || r >= H) {
                return -1;
            }
            if (food.size() > 0) {
                vector<int> f = food[0];
                if (f[0] == r && f[1] == c) {
                    food.erase(begin(food));
                    body.push_front({r, c});
                    score ++;
                    continue;
               }
            }
            body.pop_back();
            if (std::find(begin(body), end(body), vector<int>{r, c}) != body.end()) {
                return -1;
            }
            body.push_front({r, c});
        }
        return score;
    }
};
class SnakeGame {
private:
    deque<vector<int>> body;
    int W, H;
    vector<vector<int>> food;
    int score = 0;

public:
    /** Initialize your data structure here.
        @param width - screen width
        @param height - screen height 
        @param food - A list of food positions
        E.g food = [[1,1], [1,0]] means the first food is positioned at [1,1], the second is at [1,0]. */
    SnakeGame(int width, int height, vector<vector<int>>& food) {
        this->W = width;
        this->H = height;
        this->food = food;
        body.push_back({0, 0});
    }
    
    /** Moves the snake.
        @param direction - 'U' = Up, 'L' = Left, 'R' = Right, 'D' = Down 
        @return The game's score after the move. Return -1 if game over. 
        Game over when snake crosses the screen boundary or bites its body. */
    int move(string direction) {
        auto head = body.front();
        int r = head[0];
        int c = head[1];
        for (const auto &ch: direction) {
            switch (ch) {
                case 'U':
                    r --;
                    break;
                case 'L':
                    c --;
                    break;
                case 'R':
                    c ++;
                    break;
                case 'D':
                    r ++;
                    break;
                default:
                    return -1;
            }
            if (r < 0 || c < 0 || c >= W || r >= H) {
                return -1;
            }
            if (food.size() > 0) {
                vector<int> f = food[0];
                if (f[0] == r && f[1] == c) {
                    food.erase(begin(food));
                    body.push_front({r, c});
                    score ++;
                    continue;
               }
            }
            body.pop_back();
            if (std::find(begin(body), end(body), vector<int>{r, c}) != body.end()) {
                return -1;
            }
            body.push_front({r, c});
        }
        return score;
    }
};

With the above Snake Class, the game can be initialised and played:

1
2
3
4
5
/**
 * Your SnakeGame object will be instantiated and called as such:
*/
SnakeGame* obj = new SnakeGame(width, height, food);
int param_1 = obj->move(direction);
/**
 * Your SnakeGame object will be instantiated and called as such:
*/
SnakeGame* obj = new SnakeGame(width, height, food);
int param_1 = obj->move(direction);
game_over How to Design a Snake Game? c / c++ data structure design questions games

The Snake Game in Magik

Play Snake Game

Want to play the snake game? Here are two good options:

  • Simple Snake Game in Javascript
  • Chrome Extension: Snake Game

–EOF (The Ultimate Computing & Technology Blog) —

推荐阅读:
wordpress 5.4 通过区块产出更多内容,又快又简单  如何让wordpress在全国哀悼日变成黑白/灰色调  通过自定义HTML小工具为wordpress添加倒计时模块  将一个正方形纸片剪去一个宽4cm的长条  把八个数平均分成两组,使每组中四个数的积相等  用它们圆周的一部分连成一个花瓣图形  5小时后甲车行了四分之三  甲乙丙三位朋友合租一辆出租车  小红在操场上插了根1米高的竹竿  甲乙丙进行60米比赛 
评论列表
添加评论