How to Remove the Duplicates from Sorted List (Leaving Only Dist

  • 时间:2020-09-12 10:06:27
  • 分类:网络文摘
  • 阅读:97 次

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

Example 1:
Input: 1-2-3-3-4-4-5
Output: 1-2-5

Example 2:
Input: 1-1-1-2-3
Output: 2-3

Using a Hashmap to Count the Items

We can use a hashmap i.e. unordered_map in C++, to count the occurences of the items in the original linked list. This will cost O(N) time and O(N) space. However, the algorithm also applies to unsorted linked list. But it requires two passes.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        unordered_map<int, int> count;
        ListNode* p = head;
        while (p) {            
            count[p->val] ++;
            p = p->next;
        }
        ListNode* dummy = new ListNode(-1);
        p = dummy;
        while (head) {
            if (count[head->val] == 1) {
                p->next = new ListNode(head->val);
                p = p->next;
            }
            head = head->next;
        }
        return dummy->next;
    }
};
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        unordered_map<int, int> count;
        ListNode* p = head;
        while (p) {            
            count[p->val] ++;
            p = p->next;
        }
        ListNode* dummy = new ListNode(-1);
        p = dummy;
        while (head) {
            if (count[head->val] == 1) {
                p->next = new ListNode(head->val);
                p = p->next;
            }
            head = head->next;
        }
        return dummy->next;
    }
};

Skipping Duplicate Items on the Fly

The fact that the linked list is sorted helps us desgin a better algorithm. We can count the occurences of the current node in the linked list. If it is more than one, then skip it, otherwise, add the current node to the previous node – which we can update iteratedly.

This approach is O(N) time and O(1) constant space requirement.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        ListNode* dummy = new ListNode(-1);
        ListNode* prev = dummy;
        while (head) {
            int c = 0;
            ListNode *cur = head;
            while (head && head->val == cur->val) {
                c ++;
                head = head->next;
            }
            if (c == 1) {
                prev->next = cur;
                prev = cur;
            }
            cur->next = NULL;
        }        
        return dummy->next;
    }
};
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        ListNode* dummy = new ListNode(-1);
        ListNode* prev = dummy;
        while (head) {
            int c = 0;
            ListNode *cur = head;
            while (head && head->val == cur->val) {
                c ++;
                head = head->next;
            }
            if (c == 1) {
                prev->next = cur;
                prev = cur;
            }
            cur->next = NULL;
        }        
        return dummy->next;
    }
};

Depending on the requirements, you might want to delete the un-used nodes from the original linked list – in order to free the memory.

–EOF (The Ultimate Computing & Technology Blog) —

推荐阅读:
0有哪些含义  这口井有几米深?  拿破仑三角形  求甲乙两车的速度  获纪念奖的有多少人?  程大位与剩余定理  “位数”和“数位”的意义为什么不同?  节约用水的资料  求发芽率、合格率、出粉率等百分率的公式中为什么都要乘100%?  为什么公历7月和8月都是31天 
评论列表
添加评论