Bruteforce Algorithm to Compute the Maxmium Powerful Digit Sum u

  • 时间:2020-09-09 13:16:32
  • 分类:网络文摘
  • 阅读:120 次

A googol (10100) is a massive number: one followed by one-hundred zeros; 100100 is almost unimaginably large: one followed by two-hundred zeros. Despite their size, the sum of the digits in each number is only 1.

Considering natural numbers of the form, ab, where a, b < 100, what is the maximum digital sum?

Maxmium Powerful Digit Sum using Java’s BigInteger

Given a and b are in short range of [0 to 99]. There bruteforce algorithm should be more than enough to solve the problem. We need to check total 100*100 different combinations of a to the power b.

In order to hold such large number, we can use array, or in Java, we can simply use the java.math.BigInteger. See below Java’s trivial implementation using the BigInteger. The result (BigInteger) is converted to String type, then the digits are sum, then updating the maximum.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
package com.helloacm;
 
import lombok.var;
import java.math.BigInteger;
 
public class Main {
    public static void main(String[] args) {
        int ans = 0;
        for (var a = 2; a < 100; ++ a) {
            for (var b = 2; b < 100; ++ b) {
                var c = BigInteger.valueOf(a).pow(b);
                var v = c.toString();
                var sum = 0;
                for (var x: v.toCharArray()) {
                    sum += x - 48;
                    ans = Math.max(sum, ans);
                }
            }
        }
        System.out.println(ans);
    }
}
package com.helloacm;

import lombok.var;
import java.math.BigInteger;

public class Main {
    public static void main(String[] args) {
        int ans = 0;
        for (var a = 2; a < 100; ++ a) {
            for (var b = 2; b < 100; ++ b) {
                var c = BigInteger.valueOf(a).pow(b);
                var v = c.toString();
                var sum = 0;
                for (var x: v.toCharArray()) {
                    sum += x - 48;
                    ans = Math.max(sum, ans);
                }
            }
        }
        System.out.println(ans);
    }
}

The answer is 972.

–EOF (The Ultimate Computing & Technology Blog) —

推荐阅读:
SAE开发者平台的核心优势  转基因食品是福还是祸?  保健养生:花生炖食最适宜  西红柿具有较强的防癌功效  蔡甸海欣教育  面对食品安全危机,你应有的态度!  竹笋的营养与食疗保健功能  膳食平衡健康新概念“伴侣食品”  老酸奶调查:由酸奶添明胶,营养价值不高  惩罚性判罚或许可治食品安全问题之根 
评论列表
添加评论