Are Top 20 Witnesses Voting Each Other? Introducing Witness-voti

  • 时间:2020-09-09 13:08:38
  • 分类:网络文摘
  • 阅读:132 次

Let’s introduce a concept i.e. witness-voting factor that represent the average witness voting each other in the TOP 20. The maximum value is 20, and the minimal is 0.

If the witness-voting factor is 20, it means that all top 20 witnesses are voting each other. This is not healthy as the gap (of votes) between TOP 20 and the rest will be always increasing. Also, since witnesses are voting each other, it is kinda controlled by a group of people who share the same interests – this is centralisation admit it or not.

SteemJs code to compute the witness-voting factor
The idea is to retrieve the list of the votes of the TOP 20, and group them, count the frequency and sort them. Compute the average. The witness-voting factor for Top 20 on STEEM blockchain is 4.5, compared to 12.65 on HIVE.

Run the following in SteemJs Editor.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
function getTotalWitnesses() {
    return new Promise((resolve, reject) => {
      steem.api.getWitnessCount(function(err, result) {
          if (!err) {
              resolve(result);
          } else {
              reject(err);
          }
      });
    });
}
 
function getAllWitnessAccounts(total) {
    return new Promise((resolve, reject) => {
          steem.api.getWitnesses([...Array(total).keys()], function(err, result) {
            if (!err) {
                resolve(result);
            } else {
                reject(err);
           }
        });
    });
}   
 
function getAccounts(accounts) {
    return new Promise((resolve, reject) => {
          steem.api.getAccounts(accounts, function(err, result) {
            if (!err) {
                resolve(result);
            } else {
                reject(err);
           }
        });
    });
}   
 
(async function () {
    const totalWitnesses = await getTotalWitnesses();
    let data = await getAllWitnessAccounts(totalWitnesses);
    data = data.filter(x => {
        // reduce the noise
        return (x.votes > 0) && (x.running_version === "0.23.1");
    });
    // sort by votes
    data.sort((a, b) => {
        return b.votes - a.votes;
    });
    // only count TOP 20 witnesses
    data = data.slice(0, 20);
    let top = [];
    data.map((x) => {
        top.push(x.owner);
    });
    const accountData = await getAccounts(top);
    let votes = {};
    data.map((x) => {
        const account = accountData.filter(v => {
            return v.name === x.owner
        });
        // count the vote frequency for each witness
        for (let w of account[0].witness_votes) {
            if (typeof votes[w] === "undefined") {
                votes[w] = 1;
            } else {
                votes[w] ++;
            }
        }
    });    
    
    var items = Object.keys(votes).map(function(key) {
      return [key, votes[key]];
    });
    
    items.sort(function(first, second) {
      return second[1] - first[1];
    });
    
    let x = 0, cnt = 0;
    for (let w of items) {
        // TOP 20 witnesses only
        if (top.includes(w[0])) {
            log(w[0] + ", " + w[1]);
            x += w[1];
            cnt ++;
        }
    }
    log(x/cnt);
})();
function getTotalWitnesses() {
    return new Promise((resolve, reject) => {
      steem.api.getWitnessCount(function(err, result) {
          if (!err) {
              resolve(result);
          } else {
              reject(err);
          }
      });
    });
}

function getAllWitnessAccounts(total) {
    return new Promise((resolve, reject) => {
          steem.api.getWitnesses([...Array(total).keys()], function(err, result) {
            if (!err) {
                resolve(result);
            } else {
                reject(err);
           }
        });
    });
}   

function getAccounts(accounts) {
    return new Promise((resolve, reject) => {
          steem.api.getAccounts(accounts, function(err, result) {
            if (!err) {
                resolve(result);
            } else {
                reject(err);
           }
        });
    });
}   

(async function () {
    const totalWitnesses = await getTotalWitnesses();
    let data = await getAllWitnessAccounts(totalWitnesses);
    data = data.filter(x => {
        // reduce the noise
        return (x.votes > 0) && (x.running_version === "0.23.1");
    });
    // sort by votes
    data.sort((a, b) => {
        return b.votes - a.votes;
    });
    // only count TOP 20 witnesses
    data = data.slice(0, 20);
    let top = [];
    data.map((x) => {
        top.push(x.owner);
    });
    const accountData = await getAccounts(top);
    let votes = {};
    data.map((x) => {
        const account = accountData.filter(v => {
            return v.name === x.owner
        });
        // count the vote frequency for each witness
        for (let w of account[0].witness_votes) {
            if (typeof votes[w] === "undefined") {
                votes[w] = 1;
            } else {
                votes[w] ++;
            }
        }
    });    
    
    var items = Object.keys(votes).map(function(key) {
      return [key, votes[key]];
    });
    
    items.sort(function(first, second) {
      return second[1] - first[1];
    });
    
    let x = 0, cnt = 0;
    for (let w of items) {
        // TOP 20 witnesses only
        if (top.includes(w[0])) {
            log(w[0] + ", " + w[1]);
            x += w[1];
            cnt ++;
        }
    }
    log(x/cnt);
})();

Here is the detail result:

future.witness, 7
justyy, 7
steem-agora, 7
steemchiller, 7
dev.supporters, 6
dlike, 6
maiyude, 6
steem-supporter, 6
symbionts, 6
steem-dragon, 4
scissor.sisters, 4
cryptoking777, 3
hivei0, 3
hoasen, 3
juddsmith079, 3
matreshka, 3
protoss20, 3
hinomaru-jp, 2
inwi, 2
rnt1, 2

–EOF (The Ultimate Computing & Technology Blog) —

推荐阅读:
数学题:小敏要买一些圣诞卡  奥数题:一列火车匀速速度向北缓缓驶去  奥数题:小胖和小丁丁骑自行车从一条公路的两端同时出发相向而行  数学题:实际的工作效率是原计划的百分之125  数学题:将圆柱体加工成体积最大的长方体  奥数题:剩下的五盒重量是原来两盒的重量  永恒的坚守作文1200字  情人节礼物  微笑送给你我她(他)——读文章《感谢近视》有感450字  聪明的公鸡作文150字 
评论列表
添加评论