数学题:如果一个圆柱体的底面直径与高相等
- 时间:2020-06-09 15:27:22
- 分类:数学世界
- 阅读:191 次
数学题:如果一个圆柱体的底面直径与高相等,他的侧面积与表面积之比是几比几?需要解答过程。
数学题解答:如果底面直径与高相等,设底面半径是r,则直径是2r,高也是2r。然后用含有r的式子来分别表示侧面积和表面积,再求出它们的比。
也可以用设数法解决,比如设高为2厘米,则底面直径也为2厘米,底面半径是1厘米。下面就用设数法解决,条件如前面所设。
先算侧面积:3.14×2×2=12.56(平方厘米)
再算底面积:3.14×12=3.14(平方厘米)
表面积:3.14×2+12.56=18.84(平方厘米)
侧面积: 底面积 = 12.56 : 18.84 = 2:3
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