数学题:如果一个圆柱体的底面直径与高相等

  • 时间:2020-06-09 15:27:22
  • 分类:数学世界
  • 阅读:111 次

数学题:如果一个圆柱体的底面直径与高相等,他的侧面积与表面积之比是几比几?需要解答过程。

数学题解答:如果底面直径与高相等,设底面半径是r,则直径是2r,高也是2r。然后用含有r的式子来分别表示侧面积和表面积,再求出它们的比。

也可以用设数法解决,比如设高为2厘米,则底面直径也为2厘米,底面半径是1厘米。下面就用设数法解决,条件如前面所设。

先算侧面积:3.14×2×2=12.56(平方厘米)

再算底面积:3.14×12=3.14(平方厘米)

表面积:3.14×2+12.56=18.84(平方厘米)

侧面积: 底面积 = 12.56 : 18.84 = 2:3

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