运输队要运2000件玻璃器皿，按合同规定，完好无损运到的每件付运输费1.2元，如有损坏，每件没有运输费外，还要赔偿6.7元，最后运输队得到2005元，运输中损坏了多少件玻璃器皿？

数学题解答：一、假设法。假设一件也没有损坏。那么可得到1.2×2000＝2400（元），实际只得了2005元，相差395元。综合算式如下：
2000×1.2-2005）÷(6.7+1.2)=50(件)

二、方程法：设运输中损坏了X件。

2000×1.2-(6.7+1.2)X=2005
    　　　  2400-7.9X=2005
         　　　　     X=50

答：运输中损坏了50件玻璃器皿。

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