数学题:从甲袋中拿走17块巧克力,并在乙袋中放入7块巧克力
- 时间:2020-05-09 14:38:58
- 分类:数学世界
- 阅读:95 次
数学题:甲袋中的巧克力是乙袋中的五倍,如果从甲袋中拿走17块巧克力,并在乙袋中放入7块巧克力,这时甲、乙两袋巧克力块数相等,那么乙袋中原有多少块巧克力?(用方程解答。由“殇沬夕琳熏”同学提问)
数学题解答:
解:设乙袋中的巧克力是x块。
根据“这时甲、乙两袋巧克力块数相等”来列出方程。
5x-17=x+7
4x=24
x=6
答:乙袋中原有6块巧克力。
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