数学题:无线电元件厂验收一批零件
- 时间:2020-05-01 11:05:58
- 分类:数学世界
- 阅读:91 次
数学题:无线电元件厂验收一批零件,第一次验收时发现不合格产品数与合格产品数比是1:19,第二次验收时又发现有2个不合格的,这时合格率为94%,这批零件共有多少个?(并说明理由。提问者:汪战)
数学题解答:
解答此题的关键是算出后来发现2个不合格的占总数的几分之几。
第一次验收的合格率是:1919÷(19+1)=95%
第二次验收的合格率是94%。
虽然合格率变了,合格零件数变少了2个,不合格的零件数也变多了2个,但零件总数没有变。所以这2个零件占总数的:
95% – 94% = 1%
所以,零件总数是:2÷1%=200(个)
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